Here,
Number of electrons, n = 1020
Charge on each electron, e = 1.6 x 10–19 C
Time, t = 0.1 s
Total charge, Q = ne
= 1020 x 1.6 x 10–19
= 16
Current flowing through the conductor ,
Charge, Q = 1500 C
Time for which the charge is flowing, t = 5 min
Current in the wire, I = Q / t
=
Time for which charge is passing throught he lamp, t = 2 min = 2 = 120 sec
Current flowing through the lamp, I = 300 mA
Therefore,
Charge, Q = It
= 300
= 36,000
= 36 C
Given,
Number of electrons = 109
Therefore,
Total charge on the electron, q = ne
=
= 1.6 10-10
So,
Current through the wire is given by,
That is,
I =
The direction of current is opposite to the direction of electron. Hence, it is from Q to P.